| Web Enable a Form [message #83740] |
Thu, 04 December 2003 17:09 |
Quriyat
Messages: 3
Registered: December 2003
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Junior Member |
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Hi
I did the following to web enable a form.
Installed forms 6i server
Introduced registry entries for the following:
dev60temp=d:frm6ir2toolsweb60temp
forms60java=d:frm6ir2FORMS60java
dev60html=d:frm6ir2toolsweb60html
dev60cgi=d:frm6ir2toolsweb60cgi
jinitiator=d:frm6ir2JINIT
Also edited d:frm6ir2FORMS60serverformsweb.cfg for the above entries
Started the Forms server and the process ifsrv60.exe
and ifweb60.exe were running.
Copied the d2la60.dll file from d:frm6ir2bin directory to
d:frm6ir2TOOLSweb60cgi directory since 'cannot find' error was obtained
while trying to run the default form.
Installed Apache server
Verified with http://server:80 and found apache working
Modified c:Program FilesApache GroupApacheconfhttpd.conf file
to listen to port 9000;
Restarted Apache
Verified with http://server:9000 and found apache working and 80 not being active(correct).
Now if i try to restart the Forms server i get the error
FRM-60009:Network bind error; probably the port is already in use.
I installed Apache because i prefer the Apache listener over the WebDb listener.
How if i type
http://server[[domain]]:9000/dev60cgi/ifcgi60.exe?form=test.fmx&userid=&otherparams=useSDI=yes&lookAndFeel=generic&colorScheme=teal
it says "Page Cannot be Found".
TIA
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